PRECALCULUS
MATH 121

Southwestern   
Adventist University 
 
   Distance Education Lawrence E. Turner, Jr., Ph.D.  


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Series Formulas


Sum of first n positive integers

The series:

    S  =  1 + 2 + 3 + 4 + ... + n
Is a fairly useful one. Its closed form value is given by:

 Sn  =  n(n+1)
2

This can be used to derive a number of related formulas. For example, the series:

    S  =  m + m+1 + m+3 + m+4 + ... + n
can be thought of as a combination of two series: the first consisting of the integers from 1 to n and the second of the integers from 1 to m−1. That is:
    S  =  [1 + 2 + 3 + ... + m−1 + m + m+1 +... + n]   −   [1 + 2 + ... + m−1]
To get the desired sum we subtract the "1 to m−1" sum from the "1 to n" series:

 S  =  n(n+1) − (m−1)(m−1+1) = n(n+1) − m(m-1)
222

Another possibility is the sum of the first n even integers:

    Seven  =  2 + 4 + 6 + 8 + ... + 2n
We can get an expression for the sum by factoring a 2 out of each term:
    Seven  =  2[1 + 2 + 3 + 4 + ... + n]
The piece in the brackets is just the sum of the first n integers with a sum given by our formula above. Therefore, we get:
    Seven  =  2n(n+1)/2  =  n(n+1)
The sum of the first odd integers also can be teased out:
    Sodd  =  1 + 3 + 5 + ... + (2n−1)
This series has exactly n terms. If we add 1 to each term, we will have added a total of n so we can keep everything equal if we also subtract n.
    Sodd  =  (1+1) + (1+3) + (1+5) + ... + [1+(2n−1)] − n  =  [2 + 4 + 6 + ... + 2n] − n
The series with the brackets is just the sum of the first n even integers. Therefore the total becomes the rather remarkable formula:
    Sodd  =  n(n+1) − n  =  n2 + n − n  =  n2


Sum of squares of first n positive integers

The series:

    Ssquares  =  12 + 22 + 32 + 42 + ... + n2  =  1 + 4 + 9 + 25 + ... + n2
also can be evaluated, but since it is not a simple arithmetic series, the process is more difficult. The result is given by:

 Ssquares  =  n(n+1)(2n+1)
6


Sum of cubes of first n positive integers

The series:

    Scubes  =  13 + 23 + 33 + 42 + ... + n3  =  1 + 8 + 27 + 64 + ... + n3
also can be evaluated, but since it is not a simple arithmetic series, the process, like the one for the sum of the squares, is more difficult. The result is given by a particularly interesting formula:

 Scubes  =  n2(n+1)2
4

Note that this is the square of the formula for the sum of the first n integers!


Sum of higher powers of first n positive integers



We can continue with higher degree powers. Unfortunately, there is no simple pattern to the formulas and each higher power involves more work to obtain a closed form.

The series:

    S4  =  14 + 24 + 34 + 44 + ... + n4  =  1 + 16 + 81 + 256 + ... + n4
becomes

 S4  =  n(n+1)(2n + 1)(3n2 + 3n − 1)
30

The series:

    S5  =  15 + 25 + 35 + 45 + ... + n5  =  1 + 32 + 243 + 1024 + ... + n5
evaluates to

 S5  =  n2(n+1)2(2n2 + 2n − 1)
12

The series:

    S6  =  16 + 26 + 36 + 46 + ... + n6  =  1 + 64 + 729 + 4096 + ... + n6
can be computed from

 S6  =  n(n+1)(2n + 1)(3n4 + 6n3 − 3n + 1)
42

The series:

    S7  =  17 + 27 + 37 + 47 + ... + n7  =  1 + 128 + 2187 + 16384 + ... + n7
is

 S7  =  n2(n+1)2(3n4 + 6n3 − n2 − 4n + 2)
24

 

© 1999, 2000, 2001, 2002, 2003, 2004, 2005, 2006, 2008 by Lawrence Turner